Submission #2248283

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Source Code Expand

#include <iostream>

using namespace std;
using ll = long long;

int main(){
    ll N, M;
    cin >> N >> M;
    if(2*N > M){
        cout << M/2 << endl;
        return 0;
    }

    M -= 2*N;
    cout << M/4 + N << endl;
    return 0;
}

Submission Info

Judge Result